The activation energy of one of the reactions in a biochemical process is 532611 J mol–1. When the temperature falls from 310 K to 300 K, the change in rate constant observed is k300 = x × 10–3 k310. The value of x is ______.
[Given: ln10 = 2.3, R = 8.3 JK–1 mol–1]

The correct answer is: 1
\(\frac{K_{310}}{K_{300}}=10^3⇒\) \(K_{30}=1×10^{-1}×K_{310}\)




Let the shortest distance between the lines $\frac{x-3}{3} = \frac{y-\alpha}{-1} = \frac{z-3}{1}$ and $\frac{x+3}{-3} = \frac{y+7}{2} = \frac{z-\beta}{4}$ be $3\sqrt{30}$. Then the positive value of $5\alpha + \beta$ is
Uniform magnetic fields of different strengths $ B_1 $ and $ B_2 $, both normal to the plane of the paper, exist as shown in the figure. A charged particle of mass $ m $ and charge $ q $, at the interface at an instant, moves into region 2 with velocity $ v $ and returns to the interface. It continues to move into region 1 and finally reaches the interface. What is the displacement of the particle during this movement along the interface?
Consider the velocity of the particle to be normal to the magnetic field and  $ B_2 > B_1 $.
For a given reaction \( R \rightarrow P \), \( t_{1/2} \) is related to \([A_0]\) as given in the table. Given: \( \log 2 = 0.30 \). Which of the following is true? 
 
| \([A]\) (mol/L) | \(t_{1/2}\) (min) | 
|---|---|
| 0.100 | 200 | 
| 0.025 | 100 | 
A. The order of the reaction is \( \frac{1}{2} \). 
B. If \( [A_0] \) is 1 M, then \( t_{1/2} \) is \( 200/\sqrt{10} \) min. 
C. The order of the reaction changes to 1 if the concentration of reactant changes from 0.100 M to 0.500 M. 
D. \( t_{1/2} \) is 800 min for \( [A_0] = 1.6 \) M. 
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