To solve the given question, we need to correctly match each biopolymer listed in List I with its corresponding monomer from List II.
Based on these matches, the correct option is: A-II, B-III, C-I, D-IV.
| List I (Bio Polymer) | List II (Monomer) |
|---|---|
| A. Starch | II. \(\alpha\)-glucose |
| B. Cellulose | III. \(\beta\)-glucose |
| C. Nucleic acid | I. nucleotide |
| D. Protein | IV. \(\alpha\)-amino acid |
The correct matching is as follows:
- A. Starch is made up of \( \alpha \)-glucose, so \( A - II \).
- B. Cellulose is made up of \( \beta \)-glucose, so \( B - III \).
- C. Nucleic acid is made up of nucleotides, so \( C - I \).
- D. Protein is made up of amino acids, so \( D - IV \).
Hence, the correct matching is \( A - II, B - III, C - I, D - IV \).
The Correct Answer is: \( A - II, B - III, C - I, D - IV \)
Fat soluble vitamins are :
A. Vitamin B\( _1 \)
B. Vitamin C
C. Vitamin E
D. Vitamin B\( _{12} \)
E. Vitamin K
Choose the correct answer from the options given below :

Nature of compounds TeO₂ and TeH₂ is___________ and ______________respectively.