To solve the given question, we need to correctly match each biopolymer listed in List I with its corresponding monomer from List II.
Based on these matches, the correct option is: A-II, B-III, C-I, D-IV.
| List I (Bio Polymer) | List II (Monomer) |
|---|---|
| A. Starch | II. \(\alpha\)-glucose |
| B. Cellulose | III. \(\beta\)-glucose |
| C. Nucleic acid | I. nucleotide |
| D. Protein | IV. \(\alpha\)-amino acid |
The correct matching is as follows:
- A. Starch is made up of \( \alpha \)-glucose, so \( A - II \).
- B. Cellulose is made up of \( \beta \)-glucose, so \( B - III \).
- C. Nucleic acid is made up of nucleotides, so \( C - I \).
- D. Protein is made up of amino acids, so \( D - IV \).
Hence, the correct matching is \( A - II, B - III, C - I, D - IV \).
The Correct Answer is: \( A - II, B - III, C - I, D - IV \)
In the given pentapeptide, find out an essential amino acid (\(Y\)) and the sequence present in the pentapeptide. 
Choose the correct answer from the options given below:
Given below are two statements for the following reaction sequence: 
Match List-I with List-II. 
In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 
Let \( ABC \) be a triangle. Consider four points \( p_1, p_2, p_3, p_4 \) on the side \( AB \), five points \( p_5, p_6, p_7, p_8, p_9 \) on the side \( BC \), and four points \( p_{10}, p_{11}, p_{12}, p_{13} \) on the side \( AC \). None of these points is a vertex of the triangle \( ABC \). Then the total number of pentagons that can be formed by taking all the vertices from the points \( p_1, p_2, \ldots, p_{13} \) is ___________.
Consider the following two reactions A and B: 
The numerical value of [molar mass of $x$ + molar mass of $y$] is ___.