To solve the given question, we need to correctly match each biopolymer listed in List I with its corresponding monomer from List II.
Based on these matches, the correct option is: A-II, B-III, C-I, D-IV.
| List I (Bio Polymer) | List II (Monomer) |
|---|---|
| A. Starch | II. \(\alpha\)-glucose |
| B. Cellulose | III. \(\beta\)-glucose |
| C. Nucleic acid | I. nucleotide |
| D. Protein | IV. \(\alpha\)-amino acid |
The correct matching is as follows:
- A. Starch is made up of \( \alpha \)-glucose, so \( A - II \).
- B. Cellulose is made up of \( \beta \)-glucose, so \( B - III \).
- C. Nucleic acid is made up of nucleotides, so \( C - I \).
- D. Protein is made up of amino acids, so \( D - IV \).
Hence, the correct matching is \( A - II, B - III, C - I, D - IV \).
The Correct Answer is: \( A - II, B - III, C - I, D - IV \)
In the given pentapeptide, find out an essential amino acid (\(Y\)) and the sequence present in the pentapeptide. 
Choose the correct answer from the options given below:
Given below are two statements for the following reaction sequence: 
Match List-I with List-II. 
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 