$\text{The Spin only magnetic moment value of square planar complex } [\text{Pt(NH}_3\text{)}_2\text{Cl(NH}_2\text{CH}_3\text{)}]\text{Cl is } \_\_\_\_\_\_ \text{ B.M. (Nearest integer)} \\ \text{(Given atomic number for Pt = 78)}$
Correct Answer: 0
Solution and Explanation
The complex \([ \text{Pt(NH}_3)_2 \text{Cl(NH}_2\text{CH}_3) ] \text{Cl}\) contains \(\text{Pt}^{2+}\) in a square planar geometry.
\(\text{Pt}^{2+}\) has a \(d^8\) electronic configuration. In square planar complexes, the \(d\)-electrons pair up in such a way that no unpaired electrons remain. As a result, the magnetic moment is \(0 \, \text{B.M.}\) (Bohr Magnetons).
The Correct answer is: 0
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