The complex \([ \text{Pt(NH}_3)_2 \text{Cl(NH}_2\text{CH}_3) ] \text{Cl}\) contains \(\text{Pt}^{2+}\) in a square planar geometry.
\(\text{Pt}^{2+}\) has a \(d^8\) electronic configuration. In square planar complexes, the \(d\)-electrons pair up in such a way that no unpaired electrons remain. As a result, the magnetic moment is \(0 \, \text{B.M.}\) (Bohr Magnetons).
The Correct answer is: 0
The structure of the major product formed in the following reaction is:

The term independent of $ x $ in the expansion of $$ \left( \frac{x + 1}{x^{3/2} + 1 - \sqrt{x}} \cdot \frac{x + 1}{x - \sqrt{x}} \right)^{10} $$ for $ x>1 $ is:

Two cells of emf 1V and 2V and internal resistance 2 \( \Omega \) and 1 \( \Omega \), respectively, are connected in series with an external resistance of 6 \( \Omega \). The total current in the circuit is \( I_1 \). Now the same two cells in parallel configuration are connected to the same external resistance. In this case, the total current drawn is \( I_2 \). The value of \( \left( \frac{I_1}{I_2} \right) \) is \( \frac{x}{3} \). The value of x is 1cm.
If $ \theta \in [-2\pi,\ 2\pi] $, then the number of solutions of $$ 2\sqrt{2} \cos^2\theta + (2 - \sqrt{6}) \cos\theta - \sqrt{3} = 0 $$ is: