Question

Ten signals, each requiring 4000 Hz, are multiplexed onto a single channel using FDM. How much minimum bandwidth is required for the multiplexed channel? Assume that the guard bands are 400 Hz wide.

• A. 43800 Hz
• B. 46300 Hz
• C. 43600 Hz
• D. 43700 Hz

Hint:

For FDM, calculate total bandwidth as (number of signals × bandwidth per signal) + guard bands.

Answer 1

The Correct Option is A

Each signal requires 4000 Hz. For 10 signals, total bandwidth without guard bands is: 10 × 4000 = 40000 Hz. Adding guard bands: 9 × 400 = 3600 Hz. Thus, the total bandwidth is: 40000 + 3600 = 43600 Hz.