Question:
Team A plays 10 matches, probability of winning is $\frac1{3}$ and losing is $\frac2{3}$. They win x matches and lose y matches. Probability such that $|x – y| ≤ 2$ is P then find 3$^9P$.
Team A plays 10 matches, probability of winning is $\frac1{3}$ and losing is $\frac2{3}$. They win x matches and lose y matches. Probability such that $|x – y| ≤ 2$ is P then find 3$^9P$.
Updated On: Apr 5, 2024
- 8288
- 8381
- 8461
- 8911
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The Correct Option is A
Solution and Explanation
The Correct answer is option(A) : 8288
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