Question:

Taking the set of natural numbers as the universal set, write down the complements of the following sets:
(i)  {x: x is an even natural number}
(ii)  {x: x is an odd natural number}
(iii)  {x: x is a positive multiple of 3}
(iv)  {x: x is a prime number}
(v)  {x: x is a natural number divisible by 3 and 5}
(vi)  {x: x is a perfect square}
(vii)  {x: x is perfect cube}
(viii)  {x: x + 5 = 8}
(ix)  {x: 2x + 5 = 9}
(x)  {x: \(x ≥ 7\)}
(xi)  {x: x \(\in\) N and \(2x + 1 > 10\)}

Updated On: Oct 22, 2023
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Solution and Explanation

U = N: Set of natural numbers
(i) {x: x is an even natural number} ´ = {x: x is an odd natural number}


(ii) {x: x is an odd natural number} ´ = {x: x is an even natural number}


(iii) {x: x is a positive multiple of 3} ´ = {x: x \(\in\) N and x are not a multiple of 3}


(iv) {x: x is a prime number} ´ = {x: x is a positive composite number and x = 1}


(v) {x: x is a natural number divisible by 3 and 5} ´ = {x: x is a natural number that is not divisible by 3 or 5}


(vi) {x: x is a perfect square} ´ = {x: x \(\in\) N and x is not a perfect square}


(vii) {x: x is a perfect cube} ´ = {x: x \(\in\) N and x is not a perfect cube}


(viii) {x: x + 5 = 8} ´ = {x: x \(\in\) N and x\(\neq\) 3}


(ix) {x: 2x + 5 = 9} ´ = {x: x \(\in\) N and x \(\neq\) 2}


(x) {x: x \(≥\) 7} ´ = {x: x \(\in\) N and x < 7}


(xi) {x: x \(\in\) N and 2x + 1 \(>\) 10} ´ = {x: x \(∈\) N and x \(≤\frac{ 9}{2}\)}

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Concepts Used:

Complement of a Set

The complement of a set is described as A’ = {x: x ∈ U and x ∉ A}

where,

A’ stands for the complement.

Complement of Sets Properties:

1. Complement Laws: The union of a set A and its complement A’ allows the universal set U of which, A and A’ are a subset.

A ∪ A’ = U

Also, the intersection of a set A and its complement A’ cause the empty set ∅.

A ∩ A’ = ∅

For Example: If U = {11, 12 , 13 , 14 , 15 } and A = {11 , 12 , 13 } then A’ = {14 , 15}. From this it can be seen that

A ∪ A’ = U = { 11 , 12 , 13 , 14 , 15}

Also, A ∩ A’ = ∅

2. Law of Double Complementation: According to the law, if we take the complement of the complemented set A’ then, we get the set A itself.

(A’)’ = A

In the previous example we can see that, if U = {11 , 12 , 13 , 14 , 15} and A = {11 , 12, 13} then A’ ={14 , 15}. Now if we consider the complement of set ‘A’ we get,

(A’)’ = {11 , 12 , 13} = A

This gives back the set A itself.

3. Law of empty set and universal set: According to this law the complement of the universal set gives us the empty set and vice-versa i.e.,

∅’ = U And U’ = ∅

This law is accessible.