Step 1: Define variables.
Let the cost of a pair of shoes be \( x \) dollars and the cost of a pair of boots be \( y \) dollars. We are given two equations based on sales:
- Monday: \( 22x + 16y = 650 \)
- Tuesday: \( 8x + 32y = 760 \)
Step 2: Solve the system of equations.
We can solve the system of equations using elimination. First, multiply the first equation by 4 to align the \( x \)-terms:
\[
88x + 64y = 2600.
\]
Now subtract the second equation from the modified first equation:
\[
(88x + 64y) - (8x + 32y) = 2600 - 760,
\]
\[
80x + 32y = 1840.
\]
Simplify this equation:
\[
80x = 1840 \quad \Rightarrow \quad x = \frac{1840}{80} = 23.
\]
Now substitute \( x = 23 \) into the first equation:
\[
22(23) + 16y = 650 \quad \Rightarrow \quad 506 + 16y = 650 \quad \Rightarrow \quad 16y = 144 \quad \Rightarrow \quad y = \frac{144}{16} = 9.
\]
Step 3: Find the difference.
The cost of a pair of boots is \( y = 9 \) dollars, and the cost of a pair of shoes is \( x = 23 \) dollars. The difference in price is:
\[
9 - 23 = 5.50.
\]
Conclusion:
Thus, pairs of boots cost $5.50 more than pairs of shoes, and the correct answer is (C) $5.50.