Question

Suppose the line mx-y+ 5m-4=0 meets the lines x+3y+2=0, 2x+3y+4=0 and x-y-5=0 at the points R. S and T, respectively. If R, S and T are at distances r1, r2 and r3, respectively, from (-5,-4) and \((\frac{15}{r_1})^2+(\frac{10}{r_2})^2=(\frac{6}{r_3})^2\) then the value of m is

• A. \(\frac{-2}{3}\)
• B. \(\frac{2}{3}\)
• C. \(\frac{3}{2}\)
• D. \(\frac{-3}{2}\)
• E. 1

Answer 1

The Correct Option is A

The correct option is (A): \(\frac{-2}{3}\)