\[ T(P) = QP. \]
Then the rank of \( T \) is ..................Step 1: Understand the transformation
$T$ is a linear transformation that left-multiplies any $3 \times 3$ matrix $P$ by the fixed matrix $Q$.
Step 2: Represent $T$ as matrix multiplication
We can vectorize the matrices. For a matrix $P$, we can write it as a vector $\text{vec}(P)$ of dimension 9.
The transformation $T(P) = QP$ can be represented as: $$\text{vec}(QP) = (I \otimes Q)\text{vec}(P)$$
where $\otimes$ denotes the Kronecker product and $I$ is the $3 \times 3$ identity matrix.
Step 3: Find the rank of the transformation
The rank of $T$ equals the rank of the matrix representation $(I \otimes Q)$.
Property of Kronecker product: If $A$ is $m \times n$ with rank $r_A$ and $B$ is $p \times q$ with rank $r_B$, then: $$\text{rank}(A \otimes B) = r_A \cdot r_B$$
Step 4: Apply the property
Therefore: $$\text{rank}(I \otimes Q) = \text{rank}(I) \times \text{rank}(Q) = 3 \times 2 = 6$$
Answer: 6