Question:

Sulphuryl chloride $(SO_2Cl_2)$ reacts with white phosphorus $(P_4)$ to give

Updated On: Jul 15, 2024
  • $PCl_5, \, SO_2$
  • $OPCl_3,\, SOCl_2$
  • $PCl_5,\, SO_2,\, S_2Cl_2$
  • $OPCl_3,\, SO_2,\, S_2Cl_2$
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The Correct Option is A

Solution and Explanation

The correct answer is A:\(PCl_5, \, SO_2\)
When sulphuryl chloride \(\left( SO _{2} Cl _{2}\right)\) reacts with white phosphorus \(\left( P _{4}\right)\), it give phosphorus pentachloride \(\left( PCl _{5}\right)\) and' sulphur dioxide \(\left( SO _{2}\right)\). The reaction is as follows:
\(P _{4}+10\, SO _{2} Cl _{2} \longrightarrow 4 PCl _{5}+10 SO _{2}\)
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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: