Question:
Sulphuryl chloride $(SO_2Cl_2)$ reacts with white phosphorus $(P_4)$ to give
Sulphuryl chloride $(SO_2Cl_2)$ reacts with white phosphorus $(P_4)$ to give
Updated On: Jul 15, 2024
- $PCl_5, \, SO_2$
- $OPCl_3,\, SOCl_2$
- $PCl_5,\, SO_2,\, S_2Cl_2$
- $OPCl_3,\, SO_2,\, S_2Cl_2$
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The Correct Option is A
Solution and Explanation
The correct answer is A:\(PCl_5, \, SO_2\)
When sulphuryl chloride \(\left( SO _{2} Cl _{2}\right)\) reacts with white phosphorus \(\left( P _{4}\right)\), it give phosphorus pentachloride \(\left( PCl _{5}\right)\) and' sulphur dioxide \(\left( SO _{2}\right)\). The reaction is as follows:
\(P _{4}+10\, SO _{2} Cl _{2} \longrightarrow 4 PCl _{5}+10 SO _{2}\)
When sulphuryl chloride \(\left( SO _{2} Cl _{2}\right)\) reacts with white phosphorus \(\left( P _{4}\right)\), it give phosphorus pentachloride \(\left( PCl _{5}\right)\) and' sulphur dioxide \(\left( SO _{2}\right)\). The reaction is as follows:
\(P _{4}+10\, SO _{2} Cl _{2} \longrightarrow 4 PCl _{5}+10 SO _{2}\)
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family