सूचनानुसारं कृतीः कुरुत।
(च) आचार्यः तं प्रफ्ताम।
(ललकारे परिवर्तयत।)
सूचनानुसारं कृतीः कुरुत।
(च) आचार्यः तं प्रफ्ताम।
(ललकारे परिवर्तयत।)
Solution and Explanation
\[ \text{आचार्यः तं प्रप्त।} \text{(Converting into imperative form - Direct command or request.)} \]
Top Questions on व्याकरण
मैं तुमसे हमेशा पाँच साल बड़ा रहूँगा। (संयुक्त वाक्य में बदलिए।)
अपनी बात चटपट कहो और अपनी राह लो। (रचना की दृष्टि से वाक्य-भेद लिखिए।)
जैसे ही हँसी साठवें की जगह आठवीं लिखा वैसे ही सब नंबर गायब! (रचना की दृष्टि से वाक्य-भेद लिखिए।)
मेरे दरजे में आओगे, तो दोपहर पसीना आ जाएगा। (सरल वाक्य में रूपांतरित कीजिए।)
सफल खिलाड़ी का कोई निशाना खाली नहीं जाता। (मिश्र वाक्य में बदलिए।)
Questions Asked in Maharashtra Class X Board exam
- Appreciation of the poem:
Read the following poem and write an appreciation of it with the help of the points given below:
Stopping by Woods on a Snowy Evening
Whose woods these are I think I know.
His house is in the village, though;
He will not see me stopping here
To watch his woods fill up with snow
My little horse must think it queer
To stop without a farmhouse near
Between the woods and frozen lake
The darkest evening of the year.
He gives his harness bells a shake
To ask if there is some mistake.
The only other sound’s the sweep
Of easy wind and downy flake.
The woods are lovely, dark and deep,
But I have promises to keep,
And miles to go before I sleep,
And miles to go before I sleep.
Robert Frost
- Maharashtra Class X Board - 2025
- Reading Comprehension
- Pick out the infinitive from the following sentence :
He was asking to go for the concert.- Maharashtra Class X Board - 2025
- Grammar and Language Usage
- Out of the following which is a Pythagorean triplet ?
In the following figure \(\triangle\) ABC, B-D-C and BD = 7, BC = 20, then find \(\frac{A(\triangle ABD)}{A(\triangle ABC)}\).
- Maharashtra Class X Board - 2025
- Properties of Triangles
The radius of a circle with centre 'P' is 10 cm. If chord AB of the circle subtends a right angle at P, find area of minor sector by using the following activity. (\(\pi = 3.14\))
Activity :
r = 10 cm, \(\theta\) = 90\(^\circ\), \(\pi\) = 3.14.
A(P-AXB) = \(\frac{\theta}{360} \times \boxed{\phantom{\pi r^2}}\) = \(\frac{\boxed{\phantom{90}}}{360} \times 3.14 \times 10^2\) = \(\frac{1}{4} \times \boxed{\phantom{314}}\) <br>
A(P-AXB) = \(\boxed{\phantom{78.5}}\) sq. cm.