country | 2005(in '00 cases) | 2006(Rate per 10,000) | 2007(in '00 cases) |
A | 53 | 0.1 | 46 |
B | 345 | 2.1 | 145 |
C | 87 | 1.1 | 39 |
D | 81 | 33.9 | 26 |
E | 84 | 0.8 | 23 |
F | 1365 | 0..9 | 209 |
G | 661 | 13.0 | 239 |
H | 516 | 1.9 | 236 |
J | 36 | 0.2 | 16 |
K | 95 | 1.8 | 23 |
L | 262 | 3.9 | 156 |
M | 19 | 0.0 | 18 |
N | 1862 | 3.3 | 563 |
P | 47 | 56.2 | 11 |
Q | 49 | 0.5 | 18 |
R | 337 | 5.0 | 235 |
S | 61 | 1.2 | 35 |
T | 17 | 0.3 | 12 |
U | 896 | 1.5 | 235 |
V | 39 | 1.4 | 14 |
W | 31 | 0.0 | 5 |
X | 501 | 0.6 | 12 |
Y | 217 | 1.4 | 73 |
Z | 31 | 0.9 | 22 |
AA | 39 | 0.8 | 13 |
AB | 46 | 0.4 | 35 |
AC | 48 | 0.1 | 21 |
AD | 71 | 0.8 | 32 |
AE | 162 | 2.4 | 83 |
AF | 655 | 1.1 | 241 |
AG | 21,861 | 8.9 | 6445 |
AH | 869 | 1.4 | 219 |
AJ | 19 | 0.0 | 13 |
All countries that have reported more than five hundred cancers to the WHO in 2007 are listed here. The left column gives the total number of cases reported by each country for 2006, the middle column gives the 2006 rate (cancer cases per 10,000 population) and the last column shows the number of cases reported in early 2007.
Most of the 2007 reports were for only the first quarter of the year. Owing to reporting delays of six months or more, cases reported in 2007 actually were diagnosed in 2006.
Reported cases in 2006 = \(7100\)
Rate of cases reported in \(2006 = 0.8\)
Population of AD on the basis of the reported cases of cancer in 2006 (in thousands) = \(\frac{7100}{0.8}\)
\(= 875000\)
The correct option is (D): None of these
Number of cases reported in 2006:
From top to bottom:
AG = 21,861
N = 1862
F = 1365
U = 896
So, N has second highest number of cases reported in 2006.
The correct option is (A): N
Option A:
J and P have cases higher than 2000.
Option B:
A and J have higher than 2000.
Option C:
M has higher.
Option D:
All have cases lower than 2000.
The correct option is (D): M, T and AJ
1) The reported cancer cases of M, Wand AJ as compare to their population are negligible as it is 0.
2) The 2006 rate is highest for P though the reported cases are only 4700. True from the table.
3) Population of R = \(\frac{337}{5} \times10000 = 674000\)
4) P reported only 11 cases.
So, option C is correct.
The correct option is (C): I and II