Question:

Statement (A): Alkyl halides are not soluble in water.
Statement (B): Alkyl halides do not form H-bonds with water molecules through alkyl halide, but they are polar in nature. In light of the above statements, choose the most appropriate answer from the options given below:

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Remember:
  • Solubility requires both polarity and H-bonding capacity
  • Alkyl halides are polar but cannot H-bond with water
  • Small alkyl halides (e.g., $\mathrm{CH_3Cl}$) have limited water solubility
Updated On: Jun 14, 2025
  • Statement (A) is correct, B is incorrect
  • Statement (A) is incorrect, B is correct
  • Both are incorrect
  • Both statements are correct
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The Correct Option is D

Solution and Explanation

Analysis of Statement (A):
Alkyl halides ($\mathrm{R-X}$) are generally not soluble in water because:
  • They cannot form hydrogen bonds with water
  • The energy required to break water's hydrogen bonds is not compensated by new interactions
Analysis of Statement (B):
Alkyl halides are polar due to the electronegativity difference between carbon and halogen, but:
  • They cannot form hydrogen bonds with water as they lack $\mathrm{O-H}$ or $\mathrm{N-H}$ bonds
  • The halogen (X) has lone pairs but cannot donate them effectively for H-bonding
Key Observations:
1. Polarity order: $\mathrm{RI}<\mathrm{RBr}<\mathrm{RCl}<\mathrm{RF}$ (fluorides have some water solubility)
2. Solubility decreases with increasing alkyl chain length
3. Both statements correctly describe different aspects of alkyl halide properties Conclusion:
Both statements (A) and (B) are factually correct and consistent with each other.
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