Enzyme-catalyzed reactions that occur at metal surfaces often follow zero-order kinetics. This happens because, in such reactions, the reaction rate is independent of the concentration of the reactants after a certain concentration has been reached. At this point, all the enzyme active sites are occupied, and the reaction rate becomes constant, which is characteristic of zero-order reactions.
For zero-order reactions, the rate law is given by: \[ {Rate} = k \] where \( k \) is the rate constant and is independent of the reactant concentration. This is in contrast to first-order or second-order reactions where the rate depends on the concentration of the reactants.
Therefore, the correct answer is zero-order reactions, which are common for some enzyme catalyzed processes at metal surfaces.
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: