This is a linear programming problem with the objective function \( Z = 20x + 30y \) and constraints.
Step 1: Plot the constraints
We start by plotting the constraints on the graph:
1. \( x + y \leq 0 \): The line is \( x + y = 0 \), which intersects the axes at \( x = 0 \) and \( y = 0 \).
2. \( 2x + 3y \geq 100 \): The line is \( 2x + 3y = 100 \), which intersects the axes at \( x = 50 \) and \( y = 33.33 \).
3. \( x \geq 14 \): A vertical line at \( x = 14 \).
4. \( y \geq 14 \): A horizontal line at \( y = 14 \).
Step 2: Identify the feasible region
The feasible region is the area that satisfies all the constraints. The region is bounded by the lines formed by the constraints.
Step 3: Evaluate the objective function
Once we have the feasible region, evaluate \( Z = 20x + 30y \) at the vertices of the feasible region. The maximum value of \( Z \) will occur at one of these vertices.
Step 4: Find the optimal solution
After evaluating \( Z \) at the vertices, the point where \( Z \) is maximized gives the optimal solution.