Question:
solid sphere is rolling purely with speed v on horizontal surface. It rolls up an incline surface and stops at height h. Then height h is [g is the acceleration due to gravity]:
solid sphere is rolling purely with speed v on horizontal surface. It rolls up an incline surface and stops at height h. Then height h is [g is the acceleration due to gravity]:
Updated On: Jan 13, 2026
- \(\frac{3 v^2}{10} g\)
- \(\frac{7 v^2}{10} g\)
- \(\frac{5v^2}{7} g\)
- \(\frac{7v^2}{5} g\)
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The Correct Option is B
Solution and Explanation
The correct option is (B): \(\frac{7 v^2}{10} g\)
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Concepts Used:
Acceleration
In the real world, everything is always in motion. Objects move at a variable or a constant speed. When someone steps on the accelerator or applies brakes on a car, the speed of the car increases or decreases and the direction of the car changes. In physics, these changes in velocity or directional magnitude of a moving object are represented by acceleration.
