Question:

Sinusoidal carrier voltage of frequency $1.5\, MHz$ and amplitude $50\, V$ is amplitude modulated by sinusoidal voltage of frequency $10\, kHz$ producing $50 \%$ modulation. The lower and upper side-band frequencies in $kHz$ are

Updated On: Apr 15, 2024
  • 1490, 1510
  • 15101490
  • $\frac{1}{1490}, \frac{1}{1510}$
  • $\frac{1}{1510}, \frac{1}{1490}$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Here $f_{c}=1.5\, MHz =1500\, kHz ,\, f_{m}=10\, kHz$
$\therefore$ Low side-hand frequency
$=f_{c}-f_{m} =1500\, kHz -10\, kHz$
$=1490\, kHz$
Upper side-band frequency
$=f_{c}+f_{m} =1500\, kHz +10\, kHz$
$=1510\, kHz$
Was this answer helpful?
0
0