Find an anti derivative (or integral) of the following function by the method of inspection: sin 2x
Solution and Explanation
The anti derivative of sin 2x is a function of x whose derivative is sin 2x. It is known that,
\(\frac{d}{dx}\)(cos 2x)=-2sin 2x
\(\Rightarrow\) sin 2x = -\(\frac{1}{2}\frac{d}{dx}\)(cos2x)
∴ sin 2x = \(\frac{d}{dx}\bigg(-\frac{1}{2}cos2x\bigg)\)
Therefore, the anti derivative of sin 2x is -\(\frac{1}{2}\) cos 2x
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Concepts Used:
Integral
The representation of the area of a region under a curve is called to be as integral. The actual value of an integral can be acquired (approximately) by drawing rectangles.
- The definite integral of a function can be shown as the area of the region bounded by its graph of the given function between two points in the line.
- The area of a region is found by splitting it into thin vertical rectangles and applying the lower and the upper limits, the area of the region is summarized.
- An integral of a function over an interval on which the integral is described.
Also, F(x) is known to be a Newton-Leibnitz integral or antiderivative or primitive of a function f(x) on an interval I.
F'(x) = f(x)
For every value of x = I.
Types of Integrals:
Integral calculus helps to resolve two major types of problems:
- The problem of getting a function if its derivative is given.
- The problem of getting the area bounded by the graph of a function under given situations.