Question

Show the formation of ionic compound CaO with electron dot structure.

Hint:

Ca loses 2e$^-$, O gains 2e$^-$ → Ionic bond forming CaO.

Answer 1

Atomic numbers: Ca = 20, O = 8 Electronic configuration:

• Ca = 2, 8, 8, 2 (loses 2 electrons)
• O = 2, 6 (gains 2 electrons)

Formation: Calcium transfers two electrons to oxygen forming Ca$^{2+}$ and O$^{2-}$. \[ Ca \rightarrow Ca^{2+} + 2e^- \] \[ O + 2e^- \rightarrow O^{2-} \] Result: Ca$^{2+}$ and O$^{2-}$ combine to form CaO.