Show the following data by a frequency polygon:
| Electricity Bill (₹) | Families (f) |
|---|---|
| 200 - 400 | 240 |
| 400 - 600 | 300 |
| 600 - 800 | 450 |
| 800 - 1000 | 350 |
| 1000 - 1200 | 160 |
Step 1: Find the class mid-points.
Mid-point (x) = (Upper class limit + Lower class limit) / 2
| Class Interval | Mid-point (x) | Frequency (f) |
|---|---|---|
| 200 - 400 | 300 | 240 |
| 400 - 600 | 500 | 300 |
| 600 - 800 | 700 | 450 |
| 800 - 1000 | 900 | 350 |
| 1000 - 1200 | 1100 | 160 |
Step 2: Plot the points.
On a graph paper:
- Take class mid-points (x) on the X-axis.
- Take frequencies (f) on the Y-axis.
- Plot the points: (300, 240), (500, 300), (700, 450), (900, 350), (1100, 160).
Step 3: Join these points by straight lines.
To complete the polygon, join the first point to the previous mid-point (100, 0) and the last point to the next mid-point (1300, 0).
Step 4: Conclusion.
The resulting closed figure represents the Frequency Polygon for the given data.
Final Answer: Frequency Polygon drawn with mid-points (300, 500, 700, 900, 1100).
In the following figure \(\triangle\) ABC, B-D-C and BD = 7, BC = 20, then find \(\frac{A(\triangle ABD)}{A(\triangle ABC)}\). 
The radius of a circle with centre 'P' is 10 cm. If chord AB of the circle subtends a right angle at P, find area of minor sector by using the following activity. (\(\pi = 3.14\)) 
Activity :
r = 10 cm, \(\theta\) = 90\(^\circ\), \(\pi\) = 3.14.
A(P-AXB) = \(\frac{\theta}{360} \times \boxed{\phantom{\pi r^2}}\) = \(\frac{\boxed{\phantom{90}}}{360} \times 3.14 \times 10^2\) = \(\frac{1}{4} \times \boxed{\phantom{314}}\) <br>
A(P-AXB) = \(\boxed{\phantom{78.5}}\) sq. cm.