Show the following data by a frequency polygon:
| Electricity Bill (₹) | Families (f) |
|---|---|
| 200 - 400 | 240 |
| 400 - 600 | 300 |
| 600 - 800 | 450 |
| 800 - 1000 | 350 |
| 1000 - 1200 | 160 |
Step 1: Find the class mid-points.
Mid-point (x) = (Upper class limit + Lower class limit) / 2
| Class Interval | Mid-point (x) | Frequency (f) |
|---|---|---|
| 200 - 400 | 300 | 240 |
| 400 - 600 | 500 | 300 |
| 600 - 800 | 700 | 450 |
| 800 - 1000 | 900 | 350 |
| 1000 - 1200 | 1100 | 160 |
Step 2: Plot the points.
On a graph paper:
- Take class mid-points (x) on the X-axis.
- Take frequencies (f) on the Y-axis.
- Plot the points: (300, 240), (500, 300), (700, 450), (900, 350), (1100, 160).
Step 3: Join these points by straight lines.
To complete the polygon, join the first point to the previous mid-point (100, 0) and the last point to the next mid-point (1300, 0).
Step 4: Conclusion.
The resulting closed figure represents the Frequency Polygon for the given data.
Final Answer: Frequency Polygon drawn with mid-points (300, 500, 700, 900, 1100).
Let the Mean and Variance of five observations $ x_i $, $ i = 1, 2, 3, 4, 5 $ be 5 and 10 respectively. If three observations are $ x_1 = 1, x_2 = 3, x_3 = a $ and $ x_4 = 7, x_5 = b $ with $ a>b $, then the Variance of the observations $ n + x_n $ for $ n = 1, 2, 3, 4, 5 $ is
Find the variance of the following frequency distribution:
| Class Interval | ||||
| 0--4 | 4--8 | 8--12 | 12--16 | |
| Frequency | 1 | 2 | 2 | 1 |