Question:

Show the coordination number of the metal ion, its oxidation number, the number of electrons ind-orbitals and the number of unpaired electrons in d-orbitals respectively in complex $[Co(H_2O)_4SO_3 ]Cl.$

Updated On: Apr 30, 2024
  • 6, 3, 6, 4
  • 6, 3, 6, 0
  • 5, 3, 6, 4
  • 5, 3, 6, 0
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The Correct Option is A

Solution and Explanation

Coordination number is the number of monodentate ligands in the coordination sphere. Hence, the coordination number of cobait ion in $[Co(H_2O)_4 SO_3 ]Cl is 6.$
Let the oxidation number of Co is x.
x + 4(0) + (-2) + (-1) = 0
x + 0 - 2 - 1 = 0
x=3
Number of eiectrons in d-orbital are six
Number of unpaired eiectrons in d-orbitaI are 4 because $H_2O$ is a weak ligand and therefore, pairing of d-electrons in d-orbital is not possibie.
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Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.