Question:

Seven cars P, Q, R, S, T, U and V are parked in a row not necessarily in that order. The cars T and U should be parked next to each other. The cars S and V also should be parked next to each other, whereas P and Q cannot be parked next to each other. Q and S must be parked next to each other. R is parked to the immediate right of V. T is parked to the left of U. Based on the above statements, the only INCORRECT option is:

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Always place forced adjacency pairs first, then apply directional rules (left/right), and finally place restricted cars last.
  • There are two cars parked in between Q and V.
  • Q and R are not parked together.
  • V is the only car parked in between S and R.
  • Car P is parked at the extreme end.
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The Correct Option is A

Solution and Explanation

Step 1: Grouping mandatory pairs.
Q must be next to S, so QS or SQ is a block.
S must also be next to V → the only possible chain is: \[ Q - S - V \]

Step 2: Placement of R.
R is immediately to the right of V: \[ Q - S - V - R \]

Step 3: Placement of T and U.
T must be to the left of U and must be adjacent: \[ T - U \]

Step 4: Remaining car P.
P cannot be next to Q, so P must be placed on the far right end: \[ Q - S - V - R - T - U - P \] This arrangement satisfies all constraints.

Step 5: Checking the options.
(A) "There are two cars between Q and V." Actual positions: Q(1), S(2), V(3). There are zero cars between Q and V. So (A) is incorrect.
(B), (C), (D) are all consistent with the valid arrangement.
Hence, option (A) is the only incorrect statement.

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