Selected data points of the step response of a stable first-order linear time-invariant (LTI) system are given below. The closest value of the time-constant, in sec, of the system is:
Time (sec) | 0.6 | 1.6 | 2.6 | 10 | ∞ |
---|---|---|---|---|---|
Output | 0.78 | 1.65 | 2.18 | 2.98 | 3 |
y(t) = A(1 - e-t/τ)
where A = 3 is the final value and τ is the time constant. We can estimate τ using a data point.Using the value at t = 1.6, we have:
y(1.6) = 1.65 = 3(1 - e-1.6/τ) ⇒ 1.65 / 3 = 1 - e-1.6/τ ⇒ e-1.6/τ = 1 - 0.55 = 0.45 ⇒ -1.6 / τ = ln(0.45) ⇒ τ = 1.6 / -ln(0.45) ≈ 1.6 / 0.798 ≈ 2.0
Let \( G(s) = \frac{1}{(s+1)(s+2)} \). Then the closed-loop system shown in the figure below is:
The open-loop transfer function of the system shown in the figure is: \[ G(s) = \frac{K s (s + 2)}{(s + 5)(s + 7)} \] For \( K \geq 0 \), which of the following real axis point(s) is/are on the root locus?
In the Wheatstone bridge shown below, the sensitivity of the bridge in terms of change in balancing voltage \( E \) for unit change in the resistance \( R \), in V/Ω, is __________ (round off to two decimal places).
The relationship between two variables \( x \) and \( y \) is given by \( x + py + q = 0 \) and is shown in the figure. Find the values of \( p \) and \( q \). Note: The figure shown is representative.