Rolle Theorem f(x) = sin x + cos x. Find c ε [0,2,π]
To apply the Rolle's theorem to the function \(f(x) = sin x + cos x\) in the interval \([0, 2\pi]\),
we need to check the conditions of the theorem: Continuity:
The function \(f(x) = sin x + cos x\) is continuous on the interval \([0, 2\pi]\) as both sin x and cos x are continuous functions. Differentiability:
The function \(f(x) = sin x + cos x\) is differentiable on the interval \((0, 2\pi)\) as both sin x and cos x are differentiable functions.
Function values: We have \(f(0) = sin 0 + cos 0 = 0\) and \(f(2π) = sin (2π) + cos (2π) = 0\).
Since all the conditions of Rolle's theorem are satisfied, there exists at least one point c in the interval \((0, 2\pi)\) such that \(f'(c) = 0\).
To find the value of c, we need to find the derivative of f(x) and set it equal to zero: \(f'(x) = cos x - sin x\) Setting \(f'(x) = 0\),
we have \(cos x - sin x = 0\). Simplifying further, \(cos x = sin x\).
This equation is satisfied at \(x = \frac{3π}{4}\).
Therefore, in the interval \([0, 2\pi]\), there exists at least one point \(c = \frac{3π}{4}\) such that \(f'(c) = 0\).
f(x) is said to be differentiable at the point x = a, if the derivative f ‘(a) be at every point in its domain. It is given by
Mathematically, a function is said to be continuous at a point x = a, if
It is implicit that if the left-hand limit (L.H.L), right-hand limit (R.H.L), and the value of the function at x=a exist and these parameters are equal to each other, then the function f is said to be continuous at x=a.
If the function is unspecified or does not exist, then we say that the function is discontinuous.