Question:

Reverse bias applied to a junction diode

Updated On: Apr 21, 2025
  • Lowers the potential barrier
  • raises the potential barrier
  • increases the majority carrier current
  • increases the minority carrier current
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The Correct Option is B

Solution and Explanation

When a diode is reverse-biased, it increases the width of the depletion region, effectively making it more difficult for charge carriers to cross the junction. This results in a higher potential barrier for carriers trying to move from the p-side to the n-side (electrons in the case of an n-p junction).

So, the correct option is (B): raises the potential barrier

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Concepts Used:

P-n Junction

A P-N junction is an interface or a boundary between two semiconductor material types, namely the p-type and the n-type, inside a semiconductor.

Biasing conditions for the p-n Junction Diode:

in p-n junction diode two operating regions are there:

  • P-type
  • N-type

There are three biasing conditions for p-n junction diode are as follows:

  • Zero bias: When there is no external voltage applied to the p-n junction diode.
  • Forward bias: P-type is connected to positive terminal of the voltage potential while n-type is connected to the negative terminal.
  • Reverse bias: P-type is connected to negative terminal of the voltage potential while n-type is connected to the positive terminal.