The ratio of the number of organic chemicals for which the production has fallen to the number of inorganic chemicals for which production has fallen is
- 2:3
- 3:2
- 6:5
- 1:1
The Correct Option is D
Solution and Explanation
Organic chemicals for which the production has fallen =
Aniline
Acetone
Anhydride
Phenol
Inorganic chemicals for which the production has fallen =
Bleaching Powder
Alum. Chloride
Phosphate
Calcium carbonate
Calcium carbide
oxide
So, the ratio = \(4:6\)
= \(2:3\)
The correct option is (D): 1:1
Of all chemicals shown, the highest percentage increase in production has been exhibited for
- Aniline
- Ethylene glycol
- Fatty acids
- Sodium bicarbonate
The Correct Option is D
Solution and Explanation
First we have to see, for which quantities production has increased.
Highest percentage increase in production = \(\frac{[\text{Production - Previous Production}]}{\text{Previous Production}}\)
\(\%\; increase = \frac{72895 - 61615}{ 61615}\)
\(\%\;increase = \frac{11280}{61615 }\times 100\)
\(\%\; increase = 18.30\%\)
The correct option is (D): Sodium bicarbonate
The chemical, whose production in 2003-04 as a proportion of its total production for the two-year period was the lowest, is
- Aniline
- Ethylene glycol
- Fatty acids
- None of these
The Correct Option is D
Solution and Explanation
Production in 2003 - 04 as a proportion of its total production for the two-year period:
By observing from the tables, we get
Titanium oxide :
Production in \(2002 = 30422\)
Production in \(2003 = 19624\)
Proportion = \(\frac{19624}{(30422+19624)}\)
Proportion = \(\frac{19624}{50046}\)
Proportion = \(39.21\%\)
The correct option is (D): None of these
If productive volatility is defined as the percentage change in production, and it is known that any chemical whose productive volatility is greater than 5% is classified as highly volatile, then how many chemicals are not highly volatile (amongst organic chemicals)
- 6
- 5
- 4
- None of these
The Correct Option is B
Solution and Explanation
Organic chemicals:
Glycol = \(327387\times1.05\) < Production in 2003, so highly volatile
Formaldehyde = \(140384\times1.05\)>Production in 2003, so not volatile
Fatty Acids = \(99320\times1.05\)<Production in 2003, so highly volatile
Aniline = decrease in production
Acetone =decrease in production
Acetic acid= \(208921\times1.05\) < Production in 2003, so highly volatile
Anhydride = decrease in production
Benzene= \(329000\times1.05\)<Production in 2003, so highly volatile
Phenol = decrease in production
So, total value is 5.
The correct option is (B): 5
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