Question:
Read the following two statements:
Statement I: Potassium dichromate is used in volumetric analysis.
Statement II: \(K_2Cr_2O_7\) is more soluble in water than \(Na_2Cr_2O_7\)
Read the following two statements:
Statement I: Potassium dichromate is used in volumetric analysis.
Statement II: \(K_2Cr_2O_7\) is more soluble in water than \(Na_2Cr_2O_7\)
Statement I: Potassium dichromate is used in volumetric analysis.
Statement II: \(K_2Cr_2O_7\) is more soluble in water than \(Na_2Cr_2O_7\)
Show Hint
\(K_2Cr_2O_7\) is preferred as a primary standard in volumetric analysis due to its stability and consistency in aqueous solutions, even though it has lower solubility compared to \(Na_2Cr_2O_7.\)
Updated On: Mar 21, 2025
- Both statements I and II are correct.
- Both statements I and II are incorrect.
- Statement I is correct and II is incorrect
- Statement I is incorrect and II is correct.
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Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Understanding the Stability in Aqueous Solution
- K2Cr2O7: Potassium dichromate is more stable in aqueous solution, making it suitable as a primary standard.
- Na2Cr2O7: Sodium dichromate is less stable in water and tends to undergo changes in concentration, making it less suitable as a primary standard.
Conclusion for Statement I: K2Cr2O7 is preferred as a primary standard. Statement I is true.
Step 2: Solubility Comparison
- K2Cr2O7: Less soluble in water compared to Na2Cr2O7.
- Na2Cr2O7: More soluble in water than K2Cr2O7.
Conclusion for Statement II: Statement II is false because K2Cr2O7 is less soluble than Na2Cr2O7.
Final Answer:
Statement I is true, but Statement II is false.
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Classification of Matter
There are two ways of classifying the matter:
(A) Physical Classification:
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