Read the following information and complete the flowchart for the same; and give a suitable title.
Sugar beet grows through the summer and is harvested in autumn and winter. When it arrives on-site, the sugar beet is washed. The sugar beet is sliced into thin strips called cossettes.
These thin strips are mixed with hot water to extract the sugar, and a lime solution is added to the raw juice to remove any impurities.
The syrup is filtered, heated, and seeded with tiny sugar crystals, which grow into the required size. The sugar crystals are then washed, dried, and cooled. Sugar is delivered to our customers in a variety of formats for both industrial and retail markets.
Process of Sugar Production from Sugar Beet 
Step 1: Understanding the Key Steps in Sugar Production
- The process begins with the growth and harvesting of sugar beet.
- The beets are washed to remove dirt and sliced into thin strips called cossettes.
- Sugar is extracted using hot water, and a lime solution is added to purify it.
- The syrup is filtered and heated before seeding with sugar crystals.
- Finally, the sugar is washed, dried, and cooled, ready for delivery.
Step 2: Representing the Process in a Flowchart
- The steps are arranged sequentially, showing the transformation from raw sugar beet to refined sugar.
- The flowchart presents the step-by-step journey of sugar production, making it easy to understand.
You are Mr. Abhishek Sharma. You are planning to celebrate your parents’ 50th wedding anniversary in a grand manner. Draft a formal invitation card for your friends and relatives. Mention all necessary details.
In the following figure \(\triangle\) ABC, B-D-C and BD = 7, BC = 20, then find \(\frac{A(\triangle ABD)}{A(\triangle ABC)}\). 
The radius of a circle with centre 'P' is 10 cm. If chord AB of the circle subtends a right angle at P, find area of minor sector by using the following activity. (\(\pi = 3.14\)) 
Activity :
r = 10 cm, \(\theta\) = 90\(^\circ\), \(\pi\) = 3.14.
A(P-AXB) = \(\frac{\theta}{360} \times \boxed{\phantom{\pi r^2}}\) = \(\frac{\boxed{\phantom{90}}}{360} \times 3.14 \times 10^2\) = \(\frac{1}{4} \times \boxed{\phantom{314}}\) <br>
A(P-AXB) = \(\boxed{\phantom{78.5}}\) sq. cm.