Reaction of HBr with propene in the presence of peroxide gives n-propyl bromide. This addition reaction is an example of anti-Markownikoffs
addition reaction. (i.e. it is completed in form of free radical addition) \(CH_3-CH =CH_2 +HBr \xrightarrow{Peroxide}\) \(\hspace50mmCH_3-CH_2-CH_2Br\) \(\hspace50mm _{}^{\, \, \, \, \, \, \, n-propyl\, bromide}\) Mechanism of this reaction is represented as follows:
Step II Benzoate free radical forms bromine free radical with HBr.
\(C_6 H_5 CO \mathring{O}+H-Br \longrightarrow C_6 H_5 COOH +B \mathring{r}\) free radical from benzoic acid and give final product of reaction.
\(CH_3 - \mathring{C}H-CH_2 Br + C_6 H_5 COOH \longrightarrow\)
\(\hspace20mm CH_3 - CH_2-CH_2 Br + C_6 H_5 CO \mathring{O}\)
\(\hspace20mm _{}^{n-propyl\, bromide}\)
Step V Benzoate free radicals are changed into benzoyl peroxide for the termination of free radical chain.
\(C_6 H_5 CO \mathring{O}+C_6 H_5 CO \mathring{O} \longrightarrow (CC_6 H_5 CO)_2 O_2\)
Read more from the chapter: Haloalkanes and Haloarenes
The Correct Answer is (D)
The reaction of HBr with propene in the presence of peroxide gives 2-bromopropane. The real life applications are:
The Correct Answer is (D)
When an electrophile HX reacts with an alkene, the bond of the hydrogen atom will be formed at the beginning of the alkyne. This is to ensure that there is a minimum amount of hydrogen atoms. Alkenes are unsaturated hydrocarbons and have at least one double bond.
Anti-Markonikov Addition
When we talk about the Markonikov rule, If there is an unsymmetrical alkene, HBr in the presence of hydrogen peroxide. There is production of 1-bromopropane is produced in place of 2-bromopropane. This reaction is also called the anti-Markovnikov addition or the Kharash effect. It is also called as peroxide effect.
Mechanism of Anti-Markovnikov Addition
Read more:
Related Concepts | ||
---|---|---|
Peroxide | Electrophilic | Halogenation |
Carbon | Hydrogen peroxide | Huckel rule |
List-I | List-II | ||
(A) | Cyanocobalamine | (I) | Hydrogenation of Alkenes |
(B) | Wilkinson catalyst | (II) | Antipernicious anemia factor |
(C) | D-penicillamine | (III) | Refining of Ni |
(D) | Mond's Process | (IV) | Treatment of toxic effects of copper |
The molality of a 10% (v/v) solution of di-bromine solution in \(\text{CCl}_4\) (carbon tetrachloride) is \(x\). \(x = \, \_\_\_\_\ \times 10^{-2} \, \text{M}\). (Nearest integer)
Given:
Molar mass of \(\text{Br}_2 = 160 \, \text{g mol}^{-1}\)
Atomic mass of \(\text{C} = 12 \, \text{g mol}^{-1}\)
Atomic mass of \(\text{Cl} = 35.5 \, \text{g mol}^{-1}\)
Density of dibromine = \(3.2 \, \text{g cm}^{-3}\)
Density of \(\text{CCl}_4 = 1.6 \, \text{g cm}^{-3}\)
An alkene X on ozonolysis gives a mixture of Propan-2-one and methanal. What is X?
List I | List II | ||
---|---|---|---|
A | Mesozoic Era | I | Lower invertebrates |
B | Proterozoic Era | II | Fish & Amphibia |
C | Cenozoic Era | III | Birds & Reptiles |
D | Paleozoic Era | IV | Mammals |
In organic chemistry, an alkene is a hydrocarbon containing a carbon-carbon double bond.[1]
Alkene is often used as synonym of olefin, that is, any hydrocarbon containing one or more double bonds.
Read More: Ozonolysis
Read More: Unsaturated Hydrocarbon