Question

Reaction $ {CH_3CONH_2 ->[NaOBr] }$ gives

• A. $\ce{CH3Br}$
• B. $\ce{CH4}$
• C. $\ce{CH3COBr}$
• D. $\ce{CH3NH2}$

Answer 1

The Correct Option is D

This is Hofmann bromamide reaction in which $1^{\circ}$ amine is obtained having one C atom less than the starting amide.