Question

Ram and Shyam are playing a game by throwing a die alternatively till one of them gets a '\('1'\) and wins the game. The probabilities of winning by Ram and Shyam respectively if Ram starts first, is

• A. \(\frac{6}{11},\frac{5}{11}\)
• B. \(\frac{5}{11},\frac{6}{11}\)
• C. \(\frac{3}{11},\frac{8}{11}\)
• D. \(\frac{8}{11},\frac{3}{11}\)

Answer 1

The Correct Option is A

The correct option is (A): \(\frac{6}{11},\frac{5}{11}\)