Let the area of wheat and mustard cultivated by Vimal be represented as $W_v$ and $M_v$, respectively. We are given that the ratio of wheat to mustard in Vimal's land is 5 : 3. Therefore, we can express this as:
\[ \frac{W_v}{M_v} = \frac{5}{3} \quad \text{or} \quad W_v = \frac{5}{3} M_v \]
We also know that the total area of Vimal's land is 30 hectares, so:
\[ W_v + M_v = 30 \]
Substitute $W_v = \frac{5}{3} M_v$ into the equation:
\[ \frac{5}{3} M_v + M_v = 30 \]
Simplify:
\[ \frac{8}{3} M_v = 30 \implies M_v = 30 \times \frac{3}{8} = 11.25 \]
Now, substitute $M_v = 11.25$ back into $W_v = \frac{5}{3} M_v$:
\[ W_v = \frac{5}{3} \times 11.25 = 18.75 \]
So, Vimal's land has $W_v = 18.75$ hectares of wheat and $M_v = 11.25$ hectares of mustard.
Next, let's consider Rajesh's land, where the total area of wheat and mustard is divided. The total area of Rajesh's land is 20 hectares, so:
\[ W_r + M_r = 20 \]
We are also told that the overall ratio of wheat to mustard across both Rajesh's and Vimal's lands is 11 : 9, i.e.,
\[ \frac{W_v + W_r}{M_v + M_r} = \frac{11}{9} \]
Substitute the values of $W_v = 18.75$ and $M_v = 11.25$ into the equation:
\[ \frac{18.75 + W_r}{11.25 + M_r} = \frac{11}{9} \]
Cross-multiply to solve for $W_r$ and $M_r$:
\[ 9(18.75 + W_r) = 11(11.25 + M_r) \]
Simplifying:
\[ 9W_r + 168.75 = 11M_r + 123.75 \]
\[ 9W_r - 11M_r = -45 \]
We also have the equation $W_r + M_r = 20$. Now, solve this system of equations. From $W_r + M_r = 20$, express $W_r$ as:
\[ W_r = 20 - M_r \]
Substitute into the equation $9W_r - 11M_r = -45$:
\[ 9(20 - M_r) - 11M_r = -45 \]
Simplify:
\[ 180 - 9M_r - 11M_r = -45 \]
\[ 180 - 20M_r = -45 \implies -20M_r = -225 \implies M_r = 11.25 \]
Substitute $M_r = 11.25$ into $W_r + M_r = 20$:
\[ W_r = 20 - 11.25 = 8.75 \]
Finally, the ratio of the areas of wheat to mustard in Rajesh's land is:
\[ \frac{W_r}{M_r} = \frac{8.75}{11.25} = \frac{7}{9} \]
Thus, the correct answer is Option (1).