Rahul's rowing speeds upstream and downstream are provided, which we use to calculate his speed in still water and the speed of the current. Let \( v \) be the speed of Rahul in still water and \( c \) the speed of the current. The downstream speed (\( v + c \)) is given as 11 km/h, and the upstream speed (\( v - c \)) is 7 km/h.
Using these speeds, we set up the following equations:
v + c = 11 (downstream speed) v - c = 7 (upstream speed)
We can solve these equations simultaneously to find \( v \) and \( c \):
v + c = 11 v - c = 7 Adding these equations, we get: 2v = 18 v = 18 / 2 = 9 km/h
Now substituting back to find \( c \):
v + c = 11 9 + c = 11 c = 11 - 9 = 2 km/h
Thus, the speed of Rahul in still water is \( 9 \) km/h, and the speed of the current is \( 2 \) km/h. The answer corresponds to option (a).