Question:
Prussian blue is formed when
Prussian blue is formed when
Updated On: Apr 18, 2024
- ferrous sulphate reacts with FeCI$_3$
- ferric sulphate reacts with Na$_4[Fe(CN)_6$]
- ferrous ammonium sulphate reacts with FeCI$_3$
- ammonium sulphate reacts with FeCI$_3$
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The Correct Option is B
Solution and Explanation
When the sodium fusion extract is added with
FeCl$_3$ and then the resulting solution is acidified
with dilute hydrochloric acid, the appearance of
Prussian blue colouration confirms the presence of
nitrogen in the organic compound
Na + C + N $\rightarrow$ NaCN
F eSO$_4 + 2N aC N \, \, \, \rightarrow \, \, \, \, Fe(CN)_2 + Na_2SO_4$
$Fe(CN)_2 + 4N aC N \, \, \, \rightarrow \, \, \, \, Na_4[Fe(CN)_6]$
$3Na_4[Fe(CN)_6] + 4FeCl_3 \, \, \, \rightarrow \, \, \, \, Fe_4[Fe(CN)_6]_3$
$\hspace60mm $Prussian blue
$\hspace67mm $+ 12NaCl
FeCl$_3$ and then the resulting solution is acidified
with dilute hydrochloric acid, the appearance of
Prussian blue colouration confirms the presence of
nitrogen in the organic compound
Na + C + N $\rightarrow$ NaCN
F eSO$_4 + 2N aC N \, \, \, \rightarrow \, \, \, \, Fe(CN)_2 + Na_2SO_4$
$Fe(CN)_2 + 4N aC N \, \, \, \rightarrow \, \, \, \, Na_4[Fe(CN)_6]$
$3Na_4[Fe(CN)_6] + 4FeCl_3 \, \, \, \rightarrow \, \, \, \, Fe_4[Fe(CN)_6]_3$
$\hspace60mm $Prussian blue
$\hspace67mm $+ 12NaCl
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Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.