Prove that the Greatest Integer Function f: R \(\to\) R given by f(x) = [x], is neither one-once nor onto, where [x] denotes the greatest integer less than or equal to x.
f: R \(\to\) R is given by,
f(x) = [x]
It is seen that f(1.2) = [1.2] = 1, f(1.9) = [1.9] = 1.
∴ f (1.2) = f(1.9), but 1.2 ≠ 1.9.
∴ f is not one-one.
Now, consider 0.7 ∈ R.
It is known that f(x) = [x] is always an integer. Thus, there does not exist any element x ∈ R such that f(x) = 0.7.
∴ f is not onto.
Hence, the greatest integer function is neither one-one nor onto.
LIST I | LIST II | ||
A. | Range of y=cosec-1x | I. | R-(-1, 1) |
B. | Domain of sec-1x | II. | (0, π) |
C. | Domain of sin-1x | III. | [-1, 1] |
D. | Range of y=cot-1x | IV. | \([\frac{-π}{2},\frac{π}{2}]\)-{0} |
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A function is said to be one to one function when f: A → B is One to One if for each element of A there is a distinct element of B.
A function which maps two or more elements of A to the same element of set B is said to be many to one function. Two or more elements of A have the same image in B.
If there exists a function for which every element of set B there is (are) pre-image(s) in set A, it is Onto Function.
A function, f is One – One and Onto or Bijective if the function f is both One to One and Onto function.
Read More: Types of Functions