Question:

Prove that the Greatest Integer Function f:\(\to\) R given by f(x) = [x], is neither one-once nor onto, where [x] denotes the greatest integer less than or equal to x.

Updated On: Aug 26, 2023
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Solution and Explanation

f: R \(\to\) R is given by,
f(x) = [x]
It is seen that f(1.2) = [1.2] = 1, f(1.9) = [1.9] = 1.
f (1.2) = f(1.9), but 1.2 ≠ 1.9.
∴ f is not one-one.
Now, consider 0.7 ∈ R.
It is known that f(x) = [x] is always an integer. Thus, there does not exist any element x ∈ R such that f(x) = 0.7.
∴ f is not onto.

Hence, the greatest integer function is neither one-one nor onto.

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Concepts Used:

Types of Functions

Types of Functions

One to One Function

A function is said to be one to one function when f: A → B is One to One if for each element of A there is a distinct element of B. 

Many to One Function

A function which maps two or more elements of A to the same element of set B is said to be many to one function. Two or more elements of A have the same image in B.

Onto Function

If there exists a function for which every element of set B there is (are) pre-image(s) in set A, it is Onto Function. 

One – One and Onto Function

A function, f is One – One and Onto or Bijective if the function f is both One to One and Onto function.

Read More: Types of Functions