Question:

Powder diffraction experiments on samples of lead with X-rays of wavelength 1.44 $\text{\AA}$ produce (220) reflection at an angle of $32^\circ$. The lattice parameter of Lead is:

Updated On: Jan 3, 2025
  • 1.44 $\text{\AA}$
  • 2.88 $\text{\AA}$
  • 3.94 $\text{\AA}$
  • 4.02 $\text{\AA}$
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The Correct Option is C

Solution and Explanation

From Bragg's law:
\[ n\lambda = 2d \sin \theta \]
For (220) reflection, $d = \frac{a}{\sqrt{h^2 + k^2 + l^2}}$, with $h = k = 2$, $l = 0$, and $a$ being the lattice parameter:
\[ d = \frac{1.44}{2 \sin(32^\circ)} \approx 3.94 \ \text{\AA} \]

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