Point out the difference between the slavery of man to Nature and the unnatural slavery of man to Man.
Solution and Explanation
Through the chapter, the author has explored the concept of freedom. G.B. Shaw highlights the fact that no person can ever be free throughout life. The first type of slavery of man to Nature is essential in every human being. Man's slavery to Nature is always joyous. A person feels happy in fulfilling his natural needs. However, we end up becoming slaves to our instincts of cleanliness, sleep, hunger, dressing up, etc. all these natural duties are a part of every individual's daily life. However, the second type of slavey is man to man, which is unnatural. It becomes worse both physically and spiritually. It is the type of slavery where the upper hand gets favourable results, whereas hard labour yields nothing. The standard of a person is distinguished among humans. Hence, the slavery of a man to Nature gives us comfort and joy and slavery of a man to man is hatred. It creates class wars between the poor and the rich, workers and businesspeople. Ultimately, there can be no peace as long as this type of slavery exists.
Top Questions on Freedom
- When Shaw makes a statement he supports it with a number of examples. Identify two sections in the text which explain a statement with examples. Write down the main statement and the examples.
Notice how this contributes to the effectiveness of the writing. - Notice the use of personal pronouns in the two texts. Did this make you identify yourself more with the topic than if it had been written in an impersonal style? As you read the texts, were you able to relate the writer’s thoughts with the way you lead your own life?
- How does the process of inquiry lead to true freedom?
- Both the texts are on ‘freedom’. Comment on the difference in the style of treatment of the topic in them.
- ‘Nature may have tricks up her sleeve to check us if the chemists exploit her too greedily.’ Discuss.
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A compound (A) with molecular formula $C_4H_9I$ which is a primary alkyl halide, reacts with alcoholic KOH to give compound (B). Compound (B) reacts with HI to give (C) which is an isomer of (A). When (A) reacts with Na metal in the presence of dry ether, it gives a compound (D), C8H18, which is different from the compound formed when n-butyl iodide reacts with sodium. Write the structures of A, (B), (C) and (D) when (A) reacts with alcoholic KOH.
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\[ \text{Mg}(s) | \text{Mg}^{2+} (aq) || \text{Cu}^{2+} (aq) | \text{Cu}(s) \] \[ \left[ E^\circ_{\text{Mg}^{2+}/\text{Mg}} = -2.37 \, \text{V}, E^\circ_{\text{Cu}^{2+}/\text{Cu}} = +0.34 \, \text{V}, F = 96500 \, \text{C mol}^{-1} \right] \]- CBSE CLASS XII - 2025
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