To prepare phenatole (C6H5OCH2CH3), an alkoxide group (C6H5O-) can be created by deprotonating phenol (C6H5OH) with sodium (Na). This alkoxide then reacts with an alkyl halide, ethyl bromide (CH3CH2Br), to form ethoxybenzene.
Thus, the correct reactants are phenoxide (C6H5ONa) and ethyl bromide (CH3CH2Br).