Step 1: Compute interest on capital.
- A's Capital = Rs. 3,00,000 $\Rightarrow$ Interest = \( 3,00,000 \times 5% = Rs. 15,000 \)
- V's Capital = Rs. 3,00,000 $\Rightarrow$ Interest = \( 3,00,000 \times 5% = Rs. 15,000 \)
- T's Capital = Rs. 2,00,000 $\Rightarrow$ Interest = \( 2,00,000 \times 5% = Rs. 10,000 \)
Total Interest on Capital = Rs. 40,000.
Step 2: Distribute profit before guarantees.
Total Net Profit = Rs. 8,60,000
Less: Interest on Capital = Rs. 40,000
Balance Profit = Rs. 8,20,000
This balance is shared in ratio 5:3:2.
- A = \( 8,20,000 \times \frac{5}{10} = Rs. 4,10,000 \)
- V = \( 8,20,000 \times \frac{3}{10} = Rs. 2,46,000 \)
- T = \( 8,20,000 \times \frac{2}{10} = Rs. 1,64,000 \)
Step 3: Apply guarantee to T.
T is guaranteed Rs. 2,50,000 (excluding interest). Actual profit = Rs. 1,64,000.
Deficiency = \( 2,50,000 - 1,64,000 = Rs. 86,000 \).
This deficiency is to be borne by A and V in the ratio 2:3.
- A's share = \( 86,000 \times \frac{2}{5} = Rs. 34,400 \)
- V's share = \( 86,000 \times \frac{3}{5} = Rs. 51,600 \)
Final profit shares:
- A = \( 4,10,000 - 34,400 = Rs. 3,75,600 \)
- V = \( 2,46,000 - 51,600 = Rs. 1,94,400 \)
- T = \( 1,64,000 + 86,000 = Rs. 2,50,000 \)
Step 4: Consider A's guarantee of Rs. 6,00,000 fee.
Actual fee earned by A = Rs. 3,20,000.
Guaranteed fee = Rs. 6,00,000.
Deficiency = \( 6,00,000 - 3,20,000 = Rs. 2,80,000 \).
Final Answer: \[ \boxed{\text{A's deficiency of annual fee = Rs. 2,80,000}} \]
Match List-I with List-II
\[\begin{array}{|l|l|} \hline \text{List-I (Soil component)} & \text{List-II (Definition)} \\ \hline (A)~\text{Azonal soils} & (I)~\text{An individual natural aggregate of soil particles.} \\ (B)~\text{Regoliths} & (II)~\text{Organisms living in the soil or ground} \\ (C)~\text{Ped} & (III)~\text{Soils have uniformity from the top-surface to the base, and do not have well-developed soil horizons.} \\ (D)~\text{Edaphons} & (IV)~\text{Zone of loose and unconsolidated weathered rock materials.} \\ \hline \end{array}\]
Choose the correct answer from the options given below:
Match List-I with List-II
\[\begin{array}{|l|l|} \hline \text{List I Content of humus} & \text{List II Percentage of contents} \\ \hline \text{(A) Carbon} & \text{(I) 35-40\%} \\ \hline \text{(B) Oxygen} & \text{(II) ~5\%} \\ \hline \text{(C) Hydrogen} & \text{(III) 55-60\%} \\ \hline \text{(D) Nitrogen} & \text{(IV) 15\%} \\ \hline \end{array}\]
Choose the correct answer from the options given below: