Let $y = y(x)$ be a solution curve of the differential equation
$$(1 - x^2 y)\,dx = y\,dx + x\,dy.$$
If the line $x = 1$ intersects the curve $y = y(x)$ at $y = 2$
and the line $x = 2$ intersects the curve $y = y(x)$ at $y = \alpha$,
then a value of $\alpha$ is: