Step 1: Let the oxidation state of Co be \( x \). \[ 4(NH_3) + 2(H_2O) + Co + 3Cl^- = 0 \] Step 2: \( NH_3 \) and \( H_2O \) are neutral ligands, so they contribute zero charge. Chloride ion has a charge of \( -1 \) each. Total charge of three Cl\(^-\) is \(-3\). \[ x + 0 - 3 = 0 \quad \Longrightarrow \quad x = +3 \]