Question:

Oxidation number of H in NaH, CaH$_2$, and LiH, respectively is:

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In metal hydrides (e.g., NaH, CaH$_2$, LiH), hydrogen acts as a hydride ion (\( H^- \)) with an oxidation number of \(-1\). This is different from most other compounds, where hydrogen typically has an oxidation number of \(+1\).
Updated On: Apr 2, 2025
  • +1, +1, -1
  • -1, +1, +1
  • +1, +1, +1
  • -1, -1, -1
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The Correct Option is D

Solution and Explanation

1. Oxidation Number in NaH (Sodium Hydride)
Sodium (\(Na\)) is an alkali metal with a fixed oxidation number of \(+1\).
Since NaH is a neutral compound, hydrogen must have an oxidation number of \(-1\) to balance the charge. 2. Oxidation Number in CaH$_2$ (Calcium Hydride)
Calcium (\(Ca\)) is an alkaline earth metal with an oxidation number of \(+2\).
Since CaH$_2$ is neutral, hydrogen must have an oxidation number of \(-1\) to balance the charge. 3. Oxidation Number in LiH (Lithium Hydride)
Lithium (\(Li\)) is an alkali metal with an oxidation number of \(+1\).
Since LiH is neutral, hydrogen must have an oxidation number of \(-1\) to balance the charge. Final Answer: Option (d) \(-1, -1, -1\).
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