Question

Out of two-thirds of the total number of basketball matches, a team has won 17 matches and lost 3 of them. What is the maximum number of matches that the team can lose and still win more than three-fourths of the total number of matches, if it is true that no match can end in a tie?

• A. 4
• B. 6
• C. 5
• D. 3

Hint:

Convert "more than three-fourths" into inequality and solve for maximum losses.

Answer 1

The Correct Option is A

Let total matches = $T$. Played so far = $(2/3)T$, wins so far = 17. Remaining matches = $(1/3)T$, must still keep wins>$(3/4)T$. Max losses = condition: $17 + \text{rem wins}>(3/4)T$. Solve to find max losses = 4.