Let 100 kg of hematite be obtained then 20% of it get wasted that means 80 kg of ore remains.
Pure iron = 25\(\%\) of remaining ore = 80\(\times\frac{25}{100}\)
= 20 kg.
20 kg pure Iron is obtained from 100 of hematite.
1 kg pure Iron is obtained from = \(\frac{100}{20}\) hematite;
Then, 80000 kg pure Iron is obtained from = \((\frac{100}{20})\times80000\)
= 400000 kg hematite.
So the correct option is (A)