Question:

Out of the given bodies (of same mass) for which the moment of inertia will be maximum about the axis passing through its centre of gravity and perpendicular to its plane?

Updated On: Jul 2, 2022
  • Disc of radius a
  • Ring of radius a
  • Square lamina of side 2a
  • Pour rods of length 2a making a square
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The Correct Option is D

Solution and Explanation

For disc, $I=\frac{1}{2} m a^{2}$ For ring, $I=m a^{2}$ For square of side $2 a$ $=\frac{M}{12}\left[(2 a)^{2}+(2 a)^{2}\right]=\frac{2}{3} M a^{2}$ For square of rod of length $2 a$ $I=4\left[M \frac{(2 a)^{2}}{12}+M a^{2}\right]=\frac{16}{3} M a^{2}$ Hence, moment of inertia is maximum for square of four rods.
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Concepts Used:

System of Particles and Rotational Motion

  1. The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
  2. The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
  3. The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.