Question

Order and molecularity in the given reaction is
CHCl₃ + Cl₂ → CCl₄ + HCl
Rate = \(k[CHCl^3][Cl_2]^{\frac{1}{2}}\)

• A. \(\frac{3}{2}\ \text{and}\ 0\)
• B. \(\frac{3}{2}\ \text{and}\ 2\)
• C. \(\frac{3}{2}\ \text{and}\ \frac{3}{2}\)
• D. \(2\ \text{and}\ \frac{3}{2}\)

Answer 1

The Correct Option is B

The correct option is (B) :\(\frac{3}{2}\ \text{and}\ 2\).