On the horizontal surface of a truck a block of mass 1 kg is placed (µ = 0.6) and truck is moving with acceleration 5 m/s2 then the frictional force on block will be : -
5N
6N
5.88N
8N
The correct option is (A): 5N.
frL = µs.N pseudo force = ma
= µs.mg = 1 × 5
= 0.6 ×1 × 10 F = 5 N
= 6N
∴ F < frL block does not move
static firction = applied force
\(\Rightarrow\) fr = 5N
A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :
It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions.
The equations of motion in a straight line are:
v=u+at
s=ut+½ at2
v2-u2=2as
Where,