Question:
On electrolysis of aqueous sodium butanoate, the hydrocarbon formed contains how many carbon atoms?
On electrolysis of aqueous sodium butanoate, the hydrocarbon formed contains how many carbon atoms?
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In Kolbe electrolysis, two carboxylate ions lose CO\(_2\) and combine: C\(_n\) acids → C\(_{2n-2}\) hydrocarbon.
Updated On: Jan 5, 2026
- 6
- 4
- 8
- 3
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The Correct Option is A
Solution and Explanation
Kolbe electrolysis of sodium salt of butanoic acid:
\[
\begin{align}
2 \text{CH}_3\text{CH}_2\text{CH}_2\text{COO}^- \xrightarrow{\text{electrolysis}} \text{CH}_3\text{CH}_2\text{CH}_2-\text{CH}_2\text{CH}_2\text{CH}_3 + 2 \text{CO}_2
\]
Each butanoate loses CO\(_2\), and the remaining alkyl radicals combine to form a hydrocarbon with 6 carbon atoms.
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