Question:
On complete combustion of 0.492 g of an organic compound containing C, H and O, 0.7938 g of CO2 and 0.4428 g of H2O was produced. The % composition of oxygen in the compound is _______.
On complete combustion of 0.492 g of an organic compound containing C, H and O, 0.7938 g of CO2 and 0.4428 g of H2O was produced. The % composition of oxygen in the compound is _______.
Updated On: Feb 2, 2024
Hide Solution
Verified By Collegedunia
Solution and Explanation
Mole of CO2=Moles of C=\(\frac{0.793}{44}\)
Weight of 'C'=\(\frac{0.793}{44}\)×12=0.216gm
Moles of 'H' =\(\frac{0.442}{18}\)×2
Weight of 'H' =\(\frac{0.442}{18}\)×2×1=0.049gm
∴ Weight of ‘O’ =0.492−0.216−0.049=0.227gm
% of 'O' =\(\frac{0.227}{0.492}\)×100=46.13%
Was this answer helpful?
0
0
Top Questions on Organic Chemistry- Some Basic Principles and Techniques
- The most stable carbocation among the following is:
- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
- The compound that will undergo SN1 reaction with the fastest rate is
- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
- Match List I with List II
List-I
(Conversion)List-II
(Shape/geometry)(A) 1 mol of H2O to O2 (I) 3F (B) 1 mol of MnO-4 to Mn2+ (II) 2F (C) 1.5 mol of Ca from molten CaCl2 (III) 1F (D) 1 mol of FeO to Fe2O3 (IV) 5F
Choose the correct answer from the options given below:- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
- Given below are two statements :
Statement I : The boiling point of three isomeric pentanes follows the order
n-pentane > isopentane > neopentane
Statement II : When branching increases, the molecule attains a shape of sphere. This results in smaller surface area for contact, due to which the intermolecular forces between the spherical molecules are weak, thereby lowering the boiling point.
In the light of the above statements, choose the most appropriate answer from the options given below :- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
- Match List I with List II
List-I
(Complex)List-II
(Type of isomerism)(A) [Co(NH3)5(NO2)]Cl2 (I) Solvate isomerism (B) [Co(NH3)5(SO4)]Br (II) Linkage isomerism (C) [Co(NH3)6] [Cr(CN)6] (III) Ionization isomerism (D) [Co(H2O)6]Cl3 (IV) Coordination isomerism
Choose the correct answer from the options given below:- NEET (UG) - 2024
- Chemistry
- Organic Chemistry- Some Basic Principles and Techniques
View More Questions
Questions Asked in JEE Main exam
- A rectangular loop of length 2.5 m and width 2 m is placed at 60° to a magnetic field of 4 T. The loop is removed from the field in 10 sec. The average emf induced in the loop during this time is:
- JEE Main - 2024
- Electromagnetic induction
- Two coils have mutual inductance 0.002 H. The current changes in the first coil according to the relation \( i = i_0 \sin \omega t \), where \( i_0 = 5 \, \text{A} \) and \( \omega = 50\pi \, \text{rad/s} \). The maximum value of emf in the second coil is \( \frac{\pi}{\alpha} \). The value of \( \alpha \) is ______.
- JEE Main - 2024
- Electromagnetic induction
- The 20th term from the end of the progression \[ 20, 19, \frac{1}{4}, \frac{1}{2}, \frac{3}{4}, \ldots, -129 \frac{1}{4} \] is:
- JEE Main - 2024
- Arithmetic Progression
- We have three aqueous solutions of NaCl labelled as ‘A’, ‘B’ and ‘C’ with concentration 0.1 M, 0.01M & 0.001 M, respectively. The value of vant’ Haft factor (i) for these solutions will be in the order.
- JEE Main - 2024
- Colligative Properties
- $\Delta_{vap}H^\circ$ for water is $+40.49 \, \text{kJ mol}^{-1}$ at 1 bar and $100^\circ\text{C}$. Change in internal energy for this vaporisation under same condition is .............. kJ mol$^{-1}$. (Integer answer)
(Given R = 8.3 J K$^{-1}$ mol$^{-1}$)- JEE Main - 2024
- Enthalpy change
View More Questions
Concepts Used:
Organic Chemistry - Some Basic Principles and Techniques
Organic Chemistry is a subset of chemistry dealing with compounds of carbon. Therefore, we can say that Organic chemistry is the chemistry of carbon compounds and is 200-225 years old. Carbon forms bond with itself to form long chains of hydrocarbons, e.g.CH4, methane and CH3-CH3 ethane. Carbon has the ability to form carbon-carbon bonds quite elaborately. Polymers like polyethylene is a linear chain where hundreds of CH2 are linked together.
Read Also: Organic Compounds
Importance of Organic Chemistry:
Organic chemistry is applicable in a variety of areas including-
- Medicines: Example- Aspirin which is a headache medicine and Ibuprofen is a painkiller, both are organic compounds. Other examples include paracetamol.
- Food: Example- Starch which is a carbohydrate is an organic compound and a constituent of rice and other grains. It is the source of energy.
- Clothing: Example- Nylon, Polyester and Cotton are forms of organic compounds.
- Fuels: Examples- Gasoline, Petrol and Diesel are organic compounds used in the automobile industry at large.