Question:

On a given day, how many times will the second-hand and the minute-hand of a clock cross each other during the clock time 12:05:00 hours to 12:55:00 hours?

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For clock-based problems, focus on the relative speeds of the hands and the time intervals to calculate the number of crossings or alignments.
Updated On: Jan 24, 2025
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The Correct Option is C

Solution and Explanation

Step 1: Understand the motion of the second and minute hands.
The second-hand completes one full revolution (360 degrees) in 60 seconds, while the minute-hand completes one revolution in 3600 seconds (1 hour).
Step 2: Calculate the crossings in one minute.
In one minute, the second-hand crosses the minute-hand exactly once.
Step 3: Calculate the crossings between 12:05:00 and 12:55:00.
The time interval between 12:05:00 and 12:55:00 is 50 minutes. Hence, the second-hand and minute-hand will cross each other exactly 50 times during this period.
Step 4: Conclusion.
The total number of crossings is \( 50 \).
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